Respuesta :
Answer:
x = - 4
Step-by-step explanation:
Given the expression
[tex]\frac{1}{x-1} = \frac{x-2}{2x^2-2}[/tex]
This can also be expressed as;
[tex]\frac{1}{x-1} = \frac{x-2}{2(x-1)(x+1)}\\1 = \frac{x-2}{2(x+1)}[/tex]
Cross multiply
[tex]2(x+1) = x - 2\\2x+2 = x-2[/tex]
Add 2 to both sides
[tex]2x+2+2 = x-2+2\\2x+4 = x\\2x-x = -4\\x = -4[/tex]
Hence the required extraneous solution is x = -4