During a single day at radio station WMZH, the probability that a particular song is played is 1/5. What is the probability that this song will be played on exactly 3 days out of 5 days? Round your answer to the nearest thousandth.

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Answer:

the probability that the song should be played on accurately  3 days out of 5 days is 0.051

Step-by-step explanation:

Given that

The probability that a particular song is played is 1 by 5

We need to find out the probability that the song should be played on accurately  3 days out of 5 days

So,

[tex]P(x = 3) = \frac{5!}{3! (5 - 3)!} (\frac{1}{5})^3(1 - \frac{1}{5})^{5-3}[/tex]

= 0.051

Hence, the probability that the song should be played on accurately  3 days out of 5 days is 0.051

The same is considered

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