Answer:
h = 4.04 m
Explanation:
Given that,
Mass of a child, m = 25 kg
The speed of the child at the bottom of the swing is 8.9 m/s
We need to find the height in the air is the child is able to swing. Let the height is h. Using the conservation of energy such that,
[tex]mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}[/tex]
Put all the values,
[tex]h=\dfrac{(8.9)^2}{2\times 9.8}\\\\h=4.04\ m[/tex]
So, the child is able to go at a height of 4.04 m.