Answer:
1. a = - 2.5 m/s²
2. t = 2.57 s
Explanation:
1.
The acceleration of the driver can be found using the first equation of motion:
[tex]v_f = v_i + at[/tex]
where,
vf = final speed = 15 m/s
vi = initial speed = 45 m/s
a = acceleration = ?
t = time = 12 s
Therefore,
[tex]15\ m/s = 45\ m/s +a(12\ s)\\\\a = \frac{15\ m/s-45\ m/s}{12\ s}[/tex]
a = - 2.5 m/s²
negative sign indicates deceleration
2.
The time taken by the biker to accelerate can be found by using the first equation of motion again:
[tex]v_f = v_i + at[/tex]
where,
vf = final speed = 18 m/s
vi = initial speed = 0 m/s
a = acceleration = 7 m/s²
t = time = ?
Therefore,
[tex]18\ m/s = 0\ m/s +(7\ m/s^2)t\\\\t = \frac{18\ m/s}{7\ m/s^2}[/tex]
t = 2.57 s