Using an exponential function, it is found that 0.08 ml of the will be in the body in 30 hours.
The amount of a decaying substance is modeled by an exponential function in the following format:
[tex]A(t) = A(0)e^{-kt}[/tex]
In which:
In this problem, the half-life is 6 hours, which means that [tex]A(6) = 0.5A(0)[/tex], and this is used to find k.
[tex]A(t) = A(0)e^{-kt}[/tex]
[tex]0.5A(0) = A(0)e^{-6k}[/tex]
[tex]e^{-6k} = 0.5[/tex]
[tex]\ln{e^{-6k}} = \ln{0.5}[/tex]
[tex]-6k = \ln{0.5}[/tex]
[tex]k = -\frac{\ln{0.5}}{6}[/tex]
[tex]k = 0.11552453009[/tex]
Hence:
[tex]A(t) = A(0)e^{-0.11552453009t}[/tex]
2.5 ml injection, hence [tex]A(0) = 2.5[/tex]
After 30 hours, we have to find A(30), hence:
[tex]A(t) = 2.5e^{-0.11552453009t}[/tex]
[tex]A(30) = 2.5e^{-0.11552453009(30)}[/tex]
[tex]A(30) = 0.08[/tex]
0.08 ml of the will be in the body in 30 hours.
A similar problem is given at https://brainly.com/question/16984805