Answer:
Perimeter of rectangle ABCD = 32.8 unit (Approx.)
Step-by-step explanation:
Given:
Hypotenuse BD = 12 unit
Angle θ = 30°
Find:
Perimeter of rectangle ABCD
Computation:
Using trigonometry function
Sin θ = Perpendicular / Hypotenuse
Sin 30 = CD / BD
0.5 = CD / 12
Length of CD = 6 unit
Cos θ = Base / Hypotenuse
Sin 30 = BC / BD
0.866 = BC / 12
Length of BC = 10.4 unit
Perimeter of rectangle ABCD = 2[Length + Width]
Perimeter of rectangle ABCD = 2[6 + 10.4]
Perimeter of rectangle ABCD = 2[16.4]
Perimeter of rectangle ABCD = 32.8 unit (Approx.)
The perimeter of rectangle ABCD = 32.8 unit
We have given that,Hypotenuse BD = 12 unit
Angle θ = 30°
To find the perimeter of rectangle ABCD
Using trigonometry function
Sin θ = Perpendicular / Hypotenuse
Sin 30 = CD / BD
0.5 = CD / 12
Length of CD = 6 unit
Cos θ = adjucent side / Hypotenuse
Sin 30 = BC / BD
0.866 = BC / 12
Length of BC = 10.4 unit
Formula for the perimeter of rectangle ABCD = 2(Length + Width)
Perimeter of rectangle ABCD = 2(6 + 10.4)
Perimeter of rectangle ABCD = 2(16.4)
Therefore,the perimeter of rectangle ABCD = 32.8 unit
To learn more about the perimeter visit:
https://brainly.com/question/19819849
