Answer:
sec θ = [tex]\frac{6\sqrt{11} }{11}[/tex]
Step-by-step explanation:
Using the identity
sec x = [tex]\frac{1}{cosx}[/tex]
cosθ = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{\sqrt{11} }{6}[/tex] , then
secθ = [tex]\frac{6}{\sqrt{11} }[/tex] × [tex]\frac{\sqrt{11} }{\sqrt{11} }[/tex] = [tex]\frac{6\sqrt{11} }{11}[/tex]
