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Given:
The figures of triangles and their mid segments.
To find:
The values of n.
Solution:
Mid-segment theorem: According to this theorem, mid segment of the triangle is a line segment that bisect the two sides of the triangle and parallel to third side, The measure of mid-segment is half of the parallel side.
11.
It is given that:
Length of mid-segment = n+8
Length of parallel side = 6n
Using mid-segment theorem, we get
[tex]n+8=\dfrac{1}{2}(6n)[/tex]
[tex]n+8=3n[/tex]
[tex]8=3n-n[/tex]
[tex]8=2n[/tex]
Divide both side by 2.
[tex]\dfrac{8}{2}=n[/tex]
[tex]4=n[/tex]
Therefore, the value of n is equal to 4.
12.
It is given that:
Length of mid-segment = 5n
Length of parallel side = 8n+10
Using mid-segment theorem, we get
[tex]5n=\dfrac{1}{2}(8n+10)[/tex]
[tex]5n=4n+5[/tex]
[tex]5n-4n=5[/tex]
[tex]n=5[/tex]
Therefore, the value of n is equal to 5.