Question

Find the distance between the two points rounding to the nearest tenth (if necessary).
(-6, 6) and (3, -6)

Answer 1

Answer:

$\displaystyle d = 15$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Coordinates (x, y)

Algebra II

• Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-6, 6)

Point (3, -6)

Step 2: Identify

(-6, 6) → x₁ = -6, y₁ = 6

(3, -6) → x₂ = 3, y₂ = -6

Step 3: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

1. Substitute in points [Distance Formula]:                                                          $\displaystyle d = \sqrt{(3--6)^2+(-6-6)^2}$
2. [√Radical] (Parenthesis) Subtract/Add:                                                           $\displaystyle d = \sqrt{(9)^2+(-12)^2}$
3. [√Radical] Evaluate exponents:                                                                      $\displaystyle d = \sqrt{81+144}$
4. [√Radical] Add:                                                                                                 $\displaystyle d = \sqrt{225}$
5. [√Radical] Evaluate:                                                                                         $\displaystyle d = 15$