Line m is represented by the equation y + 2 = 3/2(x + 4). Select all equations that
represent lines perpendicular to line m.
A. y = -3/2x +4
B. y = -2/3x +4
C. y = 2/3x +4
D. y = 3/2x +4
E.y+1=-4/6(x+5)
F.y+ 1 = 3/2(x + 5)

Respuesta :

E. Y plus 1= 4/6(x+5)

The equations representing the lines that are perpendicular to line m are:

B. y = -2/3x +4

E. y+1=-4/6(x+5)

What is the Slope of Perpendicular Lines?

Lines that are perpendicular to each other have slopes that are negative reciprocal of each other.

For example, if a line has a slope of 2, the slope of a line that is perpendicular to it would be, -1/2 (negative reciprocal of 2).

Determine the slope of the given line whose equation is, y + 2 = 3/2(x + 4). Rewrite the equation in slope-intercept form [y = mx + b]:

y + 2 = 3/2x + 6

y = 3/2x + 6 - 2

y = 3/2x + 4

The slope is therefore 3/2.

Negative reciprocal of 3/2 is -2/3.

Examine each of the equations given and see which equation has a slope of -2/3.

A. y = -3/2x +4, the slope is -3/2.

B.  y = -2/3x + 4, the slope is -2/3. (perpendicular)

C.  y = 2/3x +4, the slope is 2/3.

D. y = 3/2x +4, the slope is 3/2.

E. y+1=-4/6(x+5), rewrite in slope-intercept form

y+1=-4/6x + 20/6

y + 1 = -2/3x + 10/3

The slope is -2/3. (perpendicular)

F. y+ 1 = 3/2(x + 5), the slope is 3/2.

Therefore, the equations representing the lines that are perpendicular to line m are:

B. y = -2/3x +4

E. y+1=-4/6(x+5)

Learn more about equations of perpendicular lines on:

https://brainly.com/question/7098341