Question

Tiffany and Dion are having a walking race. The equation and graph show the distance each person is from the starting line,
Tiffany's Distance
d = 2.5t, where d is the distance, in yards that Tiffany is from the starting line after t seconds
PLEASE ANSWER A., B. And C.

Answer 1

Answer:

Step-by-step explanation:

Tiffany's distance is defined by the equation,

d = 2.5t

Here, d = distance of Tiffany from the starting line

t = time

a). d = 2.5t

    $\frac{d}{t}=2.5$

   Tiffany's rate = 2.5 yards per second

b). Since, slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

   Slope = $\frac{y_2-y_1}{x_2-x_1}$

   Therefore, slope of the line passing through two points (0, 10) and (10, 35)

   = $\frac{35-10}{10-0}$

   = 2.5 yards per second

    Dion's walking rate = 2.5 yards per second

    Equation that defines the distance of Dione,

    d = mt + b

    Here, m = rate of the walking by Dione

    b = y-intercept

    Hence, equation will be,

    d = 2.5t + 10

c). If d = 60 yards

    For Tiffany,

    d = 2.5t

    60 = 2.5t

     t = 24 seconds

     For Dion,

     d = 2.5t + 10

     60 = 2.5t + 10

     2.5t = 50

      t = 20 seconds

     Therefore, Dion will take less time and finish first.