Question

a solution contains 32.7 g H3PO4 in 455 mL of solution. Calculate its molarity

Answer 1

Morality= wt\m.wt*1000\v(ml)

So the m.wt of h3po4 is 98.00g\ml
Molarity = 32.7g\98.00*1000\455ml
=0.7176

Answer 2

A solution contains 32.7 g of H₃PO₄ in 455 mL of solution, then the molarity of solution is 0.733 M.

How we calculate molarity?

Molarity of solution will be calculated as:

M = n/V, where

V = volume

n = moles of solute which can be calculated as:

n = W/M, where

W = given mass

M = molar mass

First we calculate the moles of 32.7g of H₃PO₄ as:

moles = 32.7g / 98 g/mol = 0.333 moles

Now we calculate molarity of H₃PO₄ in 0.455 volume as:

M = 0.333 / 0.455 = 0.733M

Hence, molarity is 0.733M.

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