Respuesta :

9514 1404 393

Answer:

  2) 198°

  4) 99°

  6) 90°

Step-by-step explanation:

The relevant relations are ...

  • an inscribed angle is half the measure of the arc it intercepts
  • the total of arcs around a circle is 360°

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2) Arc WXY = 2×angle WDY = 2(99°) = 198°

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4) Arc CLE is 2×angle CDE = 2(97°) = 194°

  Arc DE = 360° -72° -194° = 94°

  angle C = (arc DE +arc EL)/2 = (94° +104°)/2 = 99°

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6) angle C = (360° -arc EC -arc CD)/2 = (360° -71° -109°)/2 = 90°

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Answer:

2.

Given:

m arc WXY=2×99°=198°[central angle is equal to the twice of its inscribed angle]

4.Arc CLE =2x< CDE = 2×97° = 194°[central angle is equal to the twice of its inscribed angle]

again

Arc DE =360° -72° -194° = 94°[from complete turn]

and

angle C =½ (arc DE +arc EL) =½ (94° +104°) = 99°

6) angle C =½ (360° -arc EC -arc CD)

=½ (360° -71° -109°)= 90°

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