Question

Find the area of the smaller sector.
Area = [ ? ]m?
8 m
40°
YA
B
Round your answer to the nearest hundredth.

Answer 1

Answer:

area of sector is equal to

teeta × πr²

360

40 × 22 × 8×8

360. 7

22.35m

Answer 2

The area of the smaller sector OAB is 22.32 meter square.

We have a circle of radius 8 meters. Inside it, an arc AB subtends an angle $40^{o}$ at the center, due to which a smaller or minor sector OAB is formed.

We have to find out the area of this smaller sector OAB.

What is the formula to calculate the area of a sector in a circle of radius 'r' subtending an angle α at the center.

The area of the sector is given by -

$A_{sector} = \frac{\alpha \pi r^{2} }{360^{o} }$

We can use this formula to calculate the area of the smaller sector OAB, in our question -

$\alpha =40^{o}$

$r = 8\;m$

Substituting the values, we get -

$A_{sector} = \frac{40\times3.14\times8\times8}{360} \\A_{sector} = 22.32\;m^{2}$

Hence, the area of the smaller sector OAB is 22.32 meter square.

To solve more questions on finding the area of the sector, visit the link below -

https://brainly.com/question/20515973

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