Question

a rectangle has the perimeter of 116 cm and its length is 1cm more than twice its width​

Answer 1

Answer:

Find the dimensions of a rectangle given that its perimeter is 116

 cm and its length is 1

 cm more than twice its width.

 

Set up your solution using the variables L

 for the length, W

 for the width, and P

 for the perimeter. 

 

Part a: Using the definition of perimeter, what is an equation for P

 in terms of L

 and W

.

 

Part b: You also have to write an equation for L in terms of W

 in terms of W

.

 

Solve the equations from parts a and b.

 

Part c: The length is   cm.

 

Part d: The width is   cm.

Answer 2

Answer:

P=2L+2W

116=2(1+2w)+2(w)

length= 39 cm

width= 19 cm

Step-by-step explanation:

Perimeter: 116 cm                                            116=2(1+2w)+2(w)

                                                                        116=2+4w+2w

l=1+2w                                                              114=6w

____________                                                w=19

|                        |

|                        | w

|___________|