Jared bought 7 cans of paint. A can of red paint costs $3.75. A can of black paint costs $2.75. Jared spent $22.25 in all. How many cans of black (b) and how many cans of red (r) did he buy? r+b=7 3.75r+2.75b=22.25 [?] red [ black Enter​
![Jared bought 7 cans of paint A can of red paint costs 375 A can of black paint costs 275 Jared spent 2225 in all How many cans of black b and how many cans of r class=](https://us-static.z-dn.net/files/dd2/2c5d439f19dfd283890b2d2109124b9e.jpg)
Answer:
b = 4
r = 3
Step-by-step explanation:
r + b = 7
solve for 'r' to get r = 7-b
now substitute '7-b' for r in the second equation:
3.75(7-b) + 2.75b = 22.25
26.25 - 3.75b + 2.75b = 22.25
-b = -4
b = 4
r = 3
Answer: Jared bougth 4 things of black paint and 3 cans of red paint
Step-by-step explanation:
3 * 3.75 = 11.25
4 * 2.75 = 11
togther these two coe out to equaling 22.25