Question

If 15L of neon is at 25C is allowed to expand to 45L. What is the new temperature to maintain constant pressure?

Answer 1

Answer:

$T_2=894.45K=621.30\°C$

Explanation:

Hell there!

In this case, according to the given information, it turns out possible for us to calculate the new temperature by applying the Charles' law as a directly proportional relationship between temperature and volume:

$\frac{V_2}{T_2} =\frac{V_1}{T_1}$

Thus, we solve for the final temperature, T2, as shown below (make sure T1 is in Kelvins):

$T_2=\frac{V_2T_1}{V_1} \\\\T_2=\frac{(25+273.15)K*45L}{15L}\\\\T_2=894.45K=621.30\°C$

Regards!