Question

hi plz help . (6 to the power -1 + (3—2) to power -1 whole power -1​

Answer 1

$a^{-n} = \frac{1}{a^n}$

$(6^{-1} + (3-2)^{-1})^{-1} = (\frac{1}{6} + \frac{1}{3-2})^{-1} = (\frac{1}{6} + \frac{1}{1})^{-1} = (\frac{7}{6})^{-1} = \frac{6}{7}$