Question

(Total 1 mark)
Q6.
The heat released when 1.00 g of ethanol (M = 46.0) undergoes complete combustion is
29.8 kJ
What is the heat released by each molecule, in joules, when ethanol undergoes complete
combustion?
(the Avogadro constant L = 6.022 x 1029 mol')
1
19=29,86
A
2.28 10-18 u
mre 46
B
4.95 x 10-20 j
C
2.28 x 10-21 J
O
이 이
0 0
D
4.95 x 10-23 J
= 1 omoros
(Total 1 mark)

Answer 1

Answer:

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Explanation:

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Answer 2

The heat released by each molecule, in joules, when ethanol undergoes complete  combustion is 2.28 × $10^-18$ J.

The number of moles in 1.00 g  of ethanol is obtained from;

Mass of ethanol/molar mass of ethanol

Molar mass of ethanol = 46.07 g/mol

Number of moles =  1.00 g/46.07 g/mol = 0.022 moles of ethanol

1 mole of ethanol contains 6.022 × $10^23$ molecules

0.022 moles of ethanol contains  0.022 moles ×  6.022 × $10^23$ molecules/1 mole

=  1.32 × $10^22$ molecules of ethanol

If 1.32 × $10^22$ molecules of ethanol release  29.8 × $10^3$ J of heat

1 molecule of ethanol will release 1 molecule × 29.8 × 10^3 J / 1.32 × $10^22$

=  2.28 × $10^-18$ J

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