Respuesta :

Answer:

[tex]t=\sqrt{\dfrac{2s}{a}}[/tex]

Step-by-step explanation:

The given equation is :

[tex]s=ut+\dfrac{1}{2}at^2[/tex]

Where

s is displacement

u is the initial velocity

a is acceleration

t is time

If u = 0, the above equation become,

[tex]s=\dfrac{1}{2}at^2\\\\t^2=\dfrac{2s}{a}\\\\t=\sqrt{\dfrac{2s}{a}}[/tex]

Hence, the value of t is equal to [tex]\sqrt{\dfrac{2s}{a}}[/tex].