Respuesta :

Answer:

17.4 L

Explanation:

Step 1: Given data

  • Moles of oxygen (n): 0.775 mol
  • Pressure of the gas (P): 1 atm (standard pressure)
  • Temperature of the gas (T): 273.15 K (standard temperature)

Step 2: Calculate the volume occupied by 0.775 moles of oxygen at standard temperature and pressure (STP)

At STP, 1 mole of an ideal gas occupies 22.4 L.

0.775 mol × 22.4 L/1 mol = 17.4 L

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