Respuesta :

Given:

A triangle ABC.

The given expression for b is:

[tex]b=\sqrt{m+n-pq}[/tex]

To find:

The expression that is equivalent to b.

Solution:

According to the Law of Cosines,

[tex]b^2=a^2+c^2-2ac\cos B[/tex]

It can be written as:

[tex]b=\sqrt{a^2+c^2-2ac\cos B}[/tex]              ...(i)

We have,

[tex]b=\sqrt{m+n-pq}[/tex]                                ...(ii)

On comparing (i) and (ii), we get

[tex]m=a^2[/tex]

[tex]n=c^2[/tex]

[tex]p=2ac[/tex]

[tex]q=\cos B[/tex]

Therefore, the required values are [tex]m=a^2,n=c^2,p=2ac,q=\cos B[/tex].

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