Question

What volume is occupied by 0.108 mol of helium gas at a pressure of 0.96 atm and a
temperature of 315 K?

Express your answer using two significant figures.

Answer 1

Answer:

$V=2.9L$

Explanation:

Hello there!

In this case, by considering the given information in this problem, it is possible  for us to infer that this problem is solved by using the ideal gas equation:

$PV=nRT$

Next, since we are given the moles, pressure and temperature, we proceed as follows:

$V=\frac{nRT}{P}$

Then, we plug in the given data to obtain:

$V=\frac{0.108mol*0.08206\frac{atm*L}{mol*K}*315K}{0.96atm}\\\\V=2.9L$

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