Answer:
[tex]V_2=600mL[/tex]
Explanation:
Hello there!
In this case, according to this dilution process, it is possible for us to solve this problem via the following equation:
[tex]V_2M_2=V_1M_1[/tex]
Thus, since we were given the initial and final concentrations but just the initial volume, we calculate the final one as shown below:
[tex]V_2=\frac{V_1M_1}{M_2}\\\\ V_2=\frac{100.0mL*18M}{3.0M}\\\\V_2=600mL[/tex]
Regards!