Question

1. A cylinder contains600cc of ideal gas at 27°C and 650mm of pressure At constant pressure, the
volume of gas at 0°C is
(1 Point)
273cc
546cc
819cc
1365cc​

Answer 1

Answer:

$546\ \text{cc}$

Explanation:

$V_1$ = Initial volume of gas = 600 cc

$V_2$ = Final volume of gas

$T_1$ = Initial temperature of gas = $(27+273.15)\ \text{K}$

$T_2$ = Final temperature of gas = $(0+273.15)\ \text{K}$

We know that

$V\propto T$

So

$\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}\\\Rightarrow V_2=V_1\dfrac{T_2}{T_1}\\\Rightarrow V_2=600\dfrac{0+273.15}{27+273.15}\\\Rightarrow V_2=546\ \text{cc}$

The volume of gas at the given temperature is $546\ \text{cc}$