Respuesta :

Answer:  8n^6

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Work Shown:

(2n^2)^3

(2n^2)*(2n^2)*(2n^2)

(2*2*2)*(n^2*n^2*n^2)

8n^(2+2+2)

8n^6

I used the rule that a^b*a^c = a^(b+c)

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Alternative route:

(2n^2)^3

(2)^3 * (n^2)^3

8n^(2*3)

8n^6

The rules used here were (a*b)^c = (a^b)*(a^c) and (a^b)^c = a^(b*c).