Answer:
<ACB = [tex]65^{o}[/tex] and <BAC = [tex]50^{o}[/tex]
Step-by-step explanation:
The given triangle is an isosceles triangle. Thus its two sides are equal and base angles are equal.
So that;
<ACB = <ABC
<ACB = [tex]65^{o}[/tex] (property of an isosceles triangle)
Then,
<ABC + <ACB + <BAC = [tex]180^{o}[/tex]
[tex]65^{o}[/tex] + [tex]65^{o}[/tex] + <BAC = [tex]180^{o}[/tex]
130 + <BAC = [tex]180^{o}[/tex]
<BAC = [tex]180^{o}[/tex] - [tex]130^{o}[/tex]
= [tex]50^{o}[/tex]
<BAC = [tex]50^{o}[/tex]
Thus, <ACB = [tex]65^{o}[/tex] and <BAC = [tex]50^{o}[/tex].
