Question

Which function is continuous at X equals 18

Answer 1

Answer: A

Step-by-step explanation:

pretty sure :)

Answer 2

Using the continuity concept, it is found that the function that is continuous at x = 18 is given by:

$f(x) = \frac{(x - 18)^2}{x}$

What is the continuity concept?

A function f(x) is continuous at x = a if it is defined at x = a, and:

$\lim_{x \rightarrow a^-} f(x) = \lim_{x \rightarrow a^+} f(x) = f(a)$

In this problem:

• In the first function, all these characteristics are respected, hence, the function is continuous.

• For the second function, x = 18 is zero of the denominator, hence the function is not defined at x = 18.

• For the third function, the tangent is not defined at $0.5\pi$, as $\cos{0.5\pi} = 9$, hence the function is not defined at x = 18.

In the fourth function:

$f(18) = 36$

$\lim_{x \rightarrow 18^-} f(x) = 18^2 \neq 36$

Hence also not continuous.

You can learn more about the continuity concept at https://brainly.com/question/24637240