The area of the trapezium above is 22 cm².
What is the value of x ?
![The area of the trapezium above is 22 cm What is the value of x class=](https://us-static.z-dn.net/files/da7/301a2f9aa8305722288f9d103ad73133.png)
Answer:
4cm
Step-by-step explanation:
Given area= 22cm²
Height =4cm
Parallel sides = xcm and 7cm
Area of trapezium = ½( sum of parallel sides) x height
22cm² = ½(xcm+7cm)×4cm
22cm²= ½ ( x+7)cm x 4cm
opening the bracket
22cm²= 4x+28/ 2
cross multiply
44cm²=4x+28
4x=44-28
4x=16
x=4cm