In triangle MNO the measure of angle O =90 degrees the measure of angle M =66 degrees and NO = 60 feet Find the length of MN to the nearest tenth of a foot
![In triangle MNO the measure of angle O 90 degrees the measure of angle M 66 degrees and NO 60 feet Find the length of MN to the nearest tenth of a foot class=](https://us-static.z-dn.net/files/d73/f5c7686f7758a3209b62a8ec90bfa386.png)
Answer:
Length of MN = 65.68 feet (Approx.)
Step-by-step explanation:
Given:
Height of NO = 60 feet
Angle ∠M = 66°
Find:
The length of MN
Computation:
Given triangle is a right angled triangle
So,
NO is a perpendicular
MN is hypotenuse
Using trigonometry functions
Sin θ = Perpendicular / Hypotenuse
Sin 66 = NO / MN
0.9135 = 60 / Length of MN
Length of MN = 60 / 0.9135
Length of MN = 65.68 feet (Approx.)