Find the value of x for the right triangle.
trigonometric
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Here's the solution,
The given triangle is a right angled triangle,
So, by Using Trigonometry :
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[tex] \sin(30) = \dfrac{x}{13} [/tex]
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[tex] \dfrac{1}{2} = \dfrac{x}{13} [/tex]
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[tex]x = \dfrac{13}{2} [/tex]
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[tex]x = 6.5[/tex]
hence, value of x = 6.5 units