The spinner shown is divided into congruent sections that each contain a number. If the spinner is spun one time, what is the probability of NOT landing on a 1?
![The spinner shown is divided into congruent sections that each contain a number If the spinner is spun one time what is the probability of NOT landing on a 1 class=](https://us-static.z-dn.net/files/d07/8970177a36e7c76e4e0ae3fda42dbf36.png)
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Explanation:
There are 12 sections total. It might help to picture the circle split into quarters, and then each quarter is split into three pieces, giving 4*3 = 12 slices total. Or it might help to think of numbers on a round clock face.
Of these 12 sections, we have the value "1" show up exactly 4 times. That means the other values show up 12-4 = 8 times. The probability of not landing on "1" is therefore 8/12 = 2/3.
Side note: Divide both parts of 8/12 by the GCF 4 to reduce the fraction.