Question

If y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8?
Og
WN
54
0 0
96

Answer 1

Answer:

y=kx(where k is the constant of proportionality)

6=k(72)

6/72=k

k=0.08

when x is 8

y=?

making y the subject of the relation

(y=kx)

y=6/72×8

y=0.64

0r

y=kx

y=0.08×8

y=0.64