Answer:
Determine the limiting reagent
Using the stoichiometric ratios from the balanced reaction equation the mole ratio of Na : NaCl = 2 : 2.
The moles of NaCl produced by 15 moles of Na can be obtained as follows.
M
o
l
e
s
o
f
N
a
C
l
=
2
m
o
l
N
a
C
l
2
m
o
l
N
a
×
15
m
o
l
N
a
=
15
m
o
l
e
s
Using the stoichiometric ratios from the balanced reaction equation the mole ratio of
C
l
2
: NaCl = 1 : 2.
The moles of NaCl produced by 15 moles of
C
l
2
can be obtained as follows.
M
o
l
e
s
o
f
N
a
C
l
=
2
m
o
l
N
a
C
l
1
m
o
l
C
l
2
×
15
m
o
l
C
l
2
=
30
m
o
l
e
s
Since the moles of NaCl produced by Na is less than the moles produced by
C
l
2
, Na is the limiting reagent.
The theoretical yield of NaCl = Moles of NaCl produced by the limiting reagent =
15
m
o
l
Explanation:
