Question

Which of the following is the standard form of (x-7)2 + (y +1)2 = 16?

Answer 1

Answer:

$(x - 7) {}^{2} + (y + 1) {}^{2} = 16 \\ this \: is \: an \: equation \: of \: circle \\ ( {x}^{2} - 14x + 49) + ( {y}^{2} + 2y + 1) = 16 \\ {x}^{2} + {y}^{2} - 14x + 2y + 50 = 16 \\ {x}^{2} {y}^{2} - 14x + 2y + 34 = 0$