Respuesta :
Let S = student
Let A = adult
First equation is total tickets
Second should be the cost
S + A = 125
6S + 10A = 850
Use substitution or elimination
S + A = 125
S = -A + 125
I used substitution
6(-A + 125) + 10A = 850
-6A + 750 + 10A = 850
4A + 750 = 850
4A = 100, A = 25 adult tickets
125 - 25 = 100
Solution: 100 student tickets
Let A = adult
First equation is total tickets
Second should be the cost
S + A = 125
6S + 10A = 850
Use substitution or elimination
S + A = 125
S = -A + 125
I used substitution
6(-A + 125) + 10A = 850
-6A + 750 + 10A = 850
4A + 750 = 850
4A = 100, A = 25 adult tickets
125 - 25 = 100
Solution: 100 student tickets
Answer:
25 adult tickets were sold and 100 student tickets were sold.
Step-by-step explanation:
Let the number of adult tickets sold be x and the number of student tickets sold be y.
We know that the total amount collected from the tickets was $850, and that a total of 125 tickets were sold. We can use this information to come up with two equations.
10x + 6y = 850 - Equation 1
x + y = 125 - Equation 2
Then, use the substitution method to solve for either x or y first, followed by the other.
From equation two:
x + y = 125
x = 125 - y - Equation 3
Sub eqn 3 into eqn 1:
10(125-y) + 6y = 850
1250 - 10y + 6y = 850
1250 - 4y = 850
-4y = - 400
y - 100
Sub y = 100 into eqn 2:
x + 100 = 125
x = 25
Check:
10(25) + 6(100) = 850