What is the area of this figure?

Given:
A combined figure contains a square and a triangle.
To find:
The area of the given figure.
Solution:
The given figure contains a square of side 18 m and a triangle with base (8 m + 18 m)= 26 m and height height 16 m.
The area of the square is:
[tex]Area=(side)^2[/tex]
[tex]A_1=(18)^2[/tex]
[tex]A_1=324[/tex]
The area of the triangle is:
[tex]Area=\dfrac{1}{2}\times base\times height[/tex]
[tex]A_2=\dfrac{1}{2}\times 26\times 16[/tex]
[tex]A_2=13\times 16[/tex]
[tex]A_2=208[/tex]
The area of the given combined figure is:
[tex]A=A_1+A_2[/tex]
[tex]A=324+208[/tex]
[tex]A=532[/tex]
Therefore, the area of the given figure is 532 m².