Question

1. In the diagram below, the length of the legs AC and BC of right triangle ABC are 6 cm and 8 cm,
respectively. Altitude CD is drawn to the hypotenuse of AABC. What is the length of AD to the nearest tenth
of a centimeter?

Answer 1

Answer:

Note  that  ABC   is  a 6 - 8 -10   right triangle  with AB  = 10

 

Also note  that triangle ADC  is similar to triangle  ACB

 

Therefore

 

AD/ AC =  AC / AB       so

 

AD / 6  = 6/ 10           cross-multiply

 

10*AD  =  6 * 6

 

810*AD   = 36

 

AD  = 36 /  10  =    3.6  =  x

I hope this helps a little bit.