Question

Please help.
Is algebra.
PLEASE HELP NO LINKS OR FILES.
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Answer 1

Answer:

Question 5: The missing term her is r²

Question 6: The missing term here is 3.

Step-by-step explanation:

Question 5:

Let's write the equation and then solve it for the missing term. We will call this term x.

$(6r^{4}+4r)+(x-2r^{4}+3r)=4r^{4}+r^{2}+7r$

First, we simplify the letf term adding the similar terms.

$x+4r^{4}+7r=4r^{4}+r^{2}+7r$

Now, we substract 4r⁴ and 7r in both sides.

$x=r^{2}$

Therefore, the missing term her is r²

Question 6:

Here, we will call the missing term y. Now, let's solve it for y.

$(y-8x-x^{2})-(4x^{2}-7+6x)=-5x^{2}-14x+10$

Let's first distribute the minus sign into the parentehsis.

$y-8x-x^{2}-4x^{2}+7-6x=-5x^{2}-14x+10$

Now simplify the left side by adding similar terms.

$y-14x-5x^{2}+7=-5x^{2}-14x+10$

Now, let's add 14x and 5x² on both sides, then subtract 7 on both sides.

$y=10-7$

$y=3$

Therefore, the missing term here is 3.

I hope it helps you!