Question

What is the molality of a solution of 12.9 g of fructose (C6H12O6) in 31.0 g of water?

Answer 1

Answer:

2.31 $m$ C₆H₁₂O₆

Explanation:

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Answer 2

The molality of a fructose will be 2.31 M.

What is molality?

The term "total moles of a solute present in a kilogram of a solvent" is used to describe molality. The terms "molality" and "molal concentration"

Molality can be determined by the formula:

Molality = solute (n) / solvent (w) Kg

Given data:

Mass of fructose = 12.9 g

Mass of solvent = 31.0 g

Now, put the value of given data in molality equation.

Molality = 12.9/180 × 31 × $10^{-3}$

Molality = 0.00231  × $10^{-3}$

Molality = 2.31 M

Therefore, the molality of a fructose will be 2.31 M.

To know more about molality.

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