Answer:
Bella do you know the distance formula? that's the "tool" you need for these questions. :) Answers are bolded below :)
Step-by-step explanation:
dist = sqrt[ x2-x1)^2 +(y2-y1)^2]
Robins house is at Point P1 = (-9,10) in the form (x1,y1)
Sarah's house is at Point P2=(3,5) in the form (x2,y2)
dist from Robin's to Sarah's is
dist_RS = sqrt[ (3-(-9))^2 +(5-10)^2]
dist_RS = sqrt[ (3+9)^2 + (-5)^2]
dist_RS = sqrt[ 12^2 + 25 ]
dist_RS = sqrt [ 144+25]
dist_RS = sqrt [ 169]
dist_RS = 13
distance from Robin's to Jada's
where Jada's house is at Point P3 =(-3,2) in the form (x3,y3) (we can think of this as P2 in the form (x2,y2) in our formula)
dist_R J= sqrt [ (-3-(-9))^2 + (2-10)^2 ]
dist_R J= sqrt [ (-3+9)^2 + (-8)^2 ]
dist_R J= sqrt [ (6)^2 + 64 ]
dist_R J= sqrt [ 36 + 64]
dist_R J= sqrt [ 100 ]
dist_R J= 10
distance to Madison's house
where Madison's house is at Point P4 = (-1,-5) in the form (x2,y2)
dist_RM = sqrt [ (-1-(-9))^2 + (-5-10)^2 ]
dist_RM = sqrt [ (-1+9)^2 + (-15)^2 ]
dist_RM = sqrt [8^2 + 225 ]
dist_RM = sqrt [ 64 + 225 ]
dist_RM = sqrt [289 ]
dist_RM = 17
Jada's house is 10 , Madison's is 17 so it's 7 miles farther to Madison's than to Jada's
