For us to find the value of y at t equal to 7, we need to integrate first the differential equation given above. It is a variable separable equation so we can easily integrate it as follows:
dy/dt = 4y
dy/4y = dt
(integral) dy/4y = (integral) dt
(1/4) ln(y) + C = t
To determine C, we substitute y(2)=400
(1/4) ln(400) + C = 2
C = 0.5
Find y(7).
(1/4) ln(y) + 0.5 = t
(1/4) ln(y) + 0.5 = 7
(1/4) ln(y) = 6.5
ln(y) = 26
e^ln(y) = e^26
y = 1.96x10^11
