Answer:
[tex]Q=-50,307kJ[/tex]
Explanation:
Hello there!
In this case, since following reaction:
C2H4+3 O2-> 2CO2 + 2H2O
Has an enthalpy of combustion of ethene is about -1411.1 kJ/mol (can be found on goo gle), it is possible to calculate the total amount of energy that is released when 1000 grams of ethene are burned as shown below:
[tex]Q=-1411.1 \frac{kJ}{molC_2H_4} *\frac{1molC_2H_4}{28.05gC_2H_4}*1000gC_2H_4 \\\\Q=-50,307kJ[/tex]
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