Question

calculate the molarity of 0.57 moles NaHCO3 in 61.2 mL of solution. Report your answer 4 places after the decimal don’t forget to round.

Answer 1

Answer:

The correct response is "9.313 M".

Explanation:

According to the question, the values are:

Moles of solute,

= 0.57 moles

Liters of solution,

=  61.2 mL

or,

= 0.0612 L

Now,

The molarity will be:

= $\frac{Moles \ of \ solute}{Liters \ of \ solution}$

On putting the given the values in the above formula, we get

= $\frac{0.57}{0.0612}$

= $9.313 \ M$