Question

Simplify:
$\frac{6^{3}-7\cdot3^{4}-2^{5}\cdot9}{\left(1-2^{3}\right)^{3}+7^{3}}$

Answer 1

Answer:

Simplifed:

$\frac{6^{3}-7\cdot3^{4}-2^{5}\cdot9}{\left(1-2^{3}\right)^{3}+7^{3}}$

$\frac{6^{3}-7\cdot3^{4}-2^{5}\cdot9}{\left(1-2^{3}\right)^{3}+7^{3} } \\ \frac{216 - 567 -288 }{ { - 7}^{3} + {7}^{3} } \\ \frac{ - 639}{0}$

infinity