A 70kg divers steps off of a 10m tower and drops from rest straight into the water. If he comes to rest 5m beneath the surface, determine the average resistance force exerted on him by the water.
Kinetic Energy: K E= m g h h = 10 m, d = 5 m. m g ( h + d ) - F d = 0 m g ( h + d ) = F d 70 * 9.8 * 15 = F * 5 10,290 = 5 F F = 10,290 : 5 F = 2,058 N
