To solve this task we have to make a proportion, but firstly we have to set up all the main points : so, the distance is s=r(B), that has its r=radius,B=angle in rad
velocity v=ds/dt= w(r)
Do not forget about w = angular speed in rad/s and [tex] w1 = 1 revolution/sec = 2Pi (rad/s)[/tex]
Now we can go to proportion
[tex]v1=v2[/tex]
[tex] w1*r1 = w2r2 [/tex][tex]w2 = w1 * r1/r2 = 2w1 = 4Pi (rad/s)[/tex]
[tex] w2 = w3 (which is the angular velocity of the rear wheel)
[/tex]
SOLVING FOR A : [tex]v3 = w3 * r3 = 4pi * 14 (inch/s) = 14.66 ft/sec[/tex]
[tex]v3 = 14.66 ft/sec(1 mile/5280 ft)( 3600 sec/h)[/tex][tex]= 9.99 [/tex] or something about 10 mph --- SOLVING FOR B.
I'm sure it helps!