Question

A force
F acts in the x - direction, its magnitude given by F = ax^2, where x is in meters and a =5.0N/m^2
. Find the work done by this force as it acts on a particle moving from x = 0 to x = 6.0 m.

Answer 1

F = ax²
Integrating force with respect to distance yields work.
W = ax³/3
Applying limits:
W = a/3 [6³ - 0³]
W = 5/3 (216)
W = 360 Joules