Respuesta :

Answer:

51

1−2+3−4+5−.....+101

=(1+3+5+.....+101)−(2+4+6+.....+100)

=(1+3+5+.....+101)−2(1+2+3+.....+50)

=(51)

2

−2(

2

50(50+1)

)

=2601−2×1275

=2601−2550

=51

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