Answer:
x = 3 units
SV = 2 units
Step-by-step explanation:
In[tex] \odot Z[/tex] QR and ST are chords such that:
QR = ST = 4
That is both the chords are equal in measure.
Equal chords are at equal distance from the center of the circle. Therefore,
VZ = UZ
4x - 6 = 6
4x = 6 + 6
4x = 12
x = 12/4
x = 3 units
Since, perpendicular dropped from the center of the circle bisects the chord.
[tex] \therefore SV = \frac{1}{2} ST[/tex]
[tex] \therefore SV = \frac{1}{2} \times 4[/tex]
[tex] \therefore SV = 2\: units[/tex]
